Search results
Results from the WOW.Com Content Network
def get_one_random_name(letters): email_name = "" for i in range(7): email_name = email_name + random.choice(letters) return email_name Also, here is a recommandation from PEP 8: For example, do not rely on CPython's efficient implementation of in-place string concatenation for statements in the form a += b or a = a + b.
return randomVar.toString(); } It is also preferable to use for -cycle control variables. for (let x = 0; x < sel.length; x++) {. // body. } It would help readability and maintainability if you specified the types of all the arguments of all your functions. function randomIntString(min: number, max: number): string {.
In your random_char function, you don't use x at all. Replace it with _ (it's conventional in python to use _ for throwaway variables). y could also be renamed to something more descriptive. The name of the function could also be renamed to random_chars since you're generating one or more of them.
Mathematically speaking, using a cryptographically secure random number generator should yield a truly random set. The problem is clamping: if we simply take val % 10 to reduce it to our desired \$[0, 9]\$ range, we'll find that we have a slight favoritism / bias towards numbers at the lower end of the set. In fact, we should have the most bias ...
I wrote working random name generator in Java. Here's my code: NameGenerator.java: private static final String CHARACTERS = "abcdefghijklmnopqrstuvwxyz"; private static Random random = new Random(); void generate() {. WordChecker wordChecker = new WordChecker(); StringSimilarity stringSimilarity = new StringSimilarity(); Dictionary dictionary ...
StringBuilder sBuilder = new StringBuilder(); foreach (byte byt in hashBytes) sBuilder.Append(byt.ToString("x2")); return sBuilder.ToString(); You can change the method to combine random generated buffer with user's email address and then calculate hash of theme, it's more reliable.
Right now, your password generator can only generate (9×26×26) 4 (about 1.3×10 15) possible passwords. However, we can increase this to 94 12 (about 4.7×10 23 ) possible passwords by including symbols, digits, and alphabetic characters.
I've made a password generator that works fine. It takes alphabetic, numeric, and punctuation characters and randomly generates a 8-16 character password. import sys import string import random def
Instead, simply use the variable _ which conveys to the reader that your only using this loop for code repetition: for _ in range(0, random.randint(100000, 250000)): password += list_of_chars[random.randint(0, 61)] The builtin range() function will already start from zero if no other start value is specified.
1. I made a random password generator in Java using a GUI. In the program, the user can choose the length, and whether to include lowercase letters, uppercase letters, symbols or numbers in the password. I believe that my code could be much better and I want to know how I can make it so. Full code: JSlider lengthChooser; JButton genButton;